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GATE CH 2020 (with Solutions).pdf

Q6

FAILMCQpage 2holdREVIEW_LOW_CONFIDENCEP2SAMPLEUNREVIEWED
type=MCQ · page=2 · marks=1 · content_conf=0.7999999999999999 · math_conf=1

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The difference between the sum of the first 2n natural numbers and the sum of the first n odd numbers is

Options

  1. A.
    2ⁿ−n
  2. B.
    n2nn^2 - n
  3. C.
    2ⁿ+n
  4. D.
    nⁿ+n

Answer

D

Solution

The difference between the sum of first ‘2n’ natural numbers and the sum of the first ‘n’ odd positive integers are as follows First ‘2n’ natural numbers are as follows : 1,2,3,.........2n Sum=Numberofterms/2×[First term×2 + (Number of terms – 1)×Common difference]
2n[/22/times1+(2n1)/times1]2n[/22 /times 1+(2n-1) /times 1]
n(2+2n1)=n(2n+1)=2n2+nn(2+2n-1) = n(2n+1) = 2n^2+n
First ‘n’ odd positive integers are : 1,3,5,.......n
..
n[/22+2n2]=n2n[/22+2n-2] = n^2
..
Hence, the correct option is (D).

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Source PDF: GATE CH 2020 (with Solutions).pdf
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option_B2noneREVIEW
solution2noneREVIEW
solution2noneREVIEW
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Equations:none

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Issues

  • option_B_operator_set_changed_raw_vs_derived