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Consider one mole of an ideal gas in a closed system. It undergoes a change in state from L to N through two different non- isothermal processes, as shown in the P-V diagram (where P is the pressure and V is the molar volume of the gas). Process I is carried out in a single step, namely LN, whereas process II is carried out in two steps, namely LM and MN. All the steps are reversible.
(in kPa)
200N 100LM V (inm^3 mol¹)0.020.03
The net heat flowing into the system for process I is Qᵢ and that for process II is Q ᵢᵢ. The value of Qᵢ−Qᵢᵢ (in J) is
Options
- A.250
- B.500
- C.1000
- D.1500
Answer
BSolution
Wₙₑₜ=Qₙₑₜ=For a cycle
Hence, the correct option is (B).
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Source PDF:
GATE CH 2020 (with Solutions).pdf| Segment | Page | BBox | Asset | Equation | Link |
|---|---|---|---|---|---|
| stem | 29 | — | —none | — | REVIEW |
| stem | 29 | — | —none | — | REVIEW |
| solution | 29 | — | —none | — | REVIEW |
| solution | 29 | — | —none | — | REVIEW |
| solution | 29 | — | —none | — | REVIEW |
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