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GATE CH 2020 (with Solutions).pdf

Q47

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type=MCQ · page=24–25 · marks=2 · content_conf=0.7999999999999999 · math_conf=0.835

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A hollow cylinder of equal length and inner diameter (i.e., L=D) is sealed at both ends with flat plate, as shown in the figure. Its inner surfaces A A and A radiate energy.
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Options

  1. A.
    F_2_1 = 2-1
  2. B.
    F21=/frac(21)2F_{21} = /frac{(2-1)}{2}
  3. C.
    F21=/frac(21)4F_{21} = /frac{(2-1)}{4}
  4. D.
    F21=/frac(21)8F_{21} = /frac{(2-1)}{8}

Answer

B

Solution

..
Given, F₁ ₃=3 − 2 2 & L=D
F11+F12+F13=1F_{11}+F_{12}+F_{13} = 1
0+F12+322=10+F_{12}+3-22 = 1
F_1_2 = 22-2
From Reciprocity theorem
A1F12=A2F21F21=/fracA1A2/timesF12A_1F_{12} = A_2F_{21} ⇒ F_{21} = /frac{A_1}{A_2} /times F_{12}
F21=/frac/πR22/πRL/times(222)F_{21} = /frac{/\pi{}{}R^2}{2/\pi{}{}RL} /times (22-2)
F21=/frac/πR22/πR(2R)/times(222)F_{21} = /frac{/\pi{}{}R^2}{2/\pi{}{}R}(2R) /times (22-2)
F21=/frac(21)2F_{21} = /frac{(2-1)}{2}
Hence, the correct option is (B).

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Source PDF: GATE CH 2020 (with Solutions).pdf
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  • structurePASS
  • question_textPASS
  • optionsFAIL
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  • option_B_operator_set_changed_raw_vs_derived
  • option_C_operator_set_changed_raw_vs_derived
  • option_D_operator_set_changed_raw_vs_derived